(9x^2+7x-4)-(9x^2+3)=21

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Solution for (9x^2+7x-4)-(9x^2+3)=21 equation:


Simplifying
(9x2 + 7x + -4) + -1(9x2 + 3) = 21

Reorder the terms:
(-4 + 7x + 9x2) + -1(9x2 + 3) = 21

Remove parenthesis around (-4 + 7x + 9x2)
-4 + 7x + 9x2 + -1(9x2 + 3) = 21

Reorder the terms:
-4 + 7x + 9x2 + -1(3 + 9x2) = 21
-4 + 7x + 9x2 + (3 * -1 + 9x2 * -1) = 21
-4 + 7x + 9x2 + (-3 + -9x2) = 21

Reorder the terms:
-4 + -3 + 7x + 9x2 + -9x2 = 21

Combine like terms: -4 + -3 = -7
-7 + 7x + 9x2 + -9x2 = 21

Combine like terms: 9x2 + -9x2 = 0
-7 + 7x + 0 = 21
-7 + 7x = 21

Solving
-7 + 7x = 21

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 7x = 21 + 7

Combine like terms: -7 + 7 = 0
0 + 7x = 21 + 7
7x = 21 + 7

Combine like terms: 21 + 7 = 28
7x = 28

Divide each side by '7'.
x = 4

Simplifying
x = 4

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